vasorasy8

2022-07-07

How do you solve $12<8+x$ ?

Jayvion Tyler

Expert

Step 1
Subtract 8 from both sides to get
$12-8<\overline{)8}+x-\overline{)8}$
The left hand side becomes $12-8=4$ and so we have
$4
which is the same as
$x>4$

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