A measurement of the traffic generated by the packet source indicates that the average traffic...

pipantasi4

pipantasi4

Answered

2022-07-08

A measurement of the traffic generated by the packet source indicates that the average traffic is λ [packets/s] and maximum traffic is σ [packets/s]. The classic exponential distribution is not appropriate for modeling such a source of traffic, because the exponential distribution contains only one parameter (and two parameters were measured).
To model such a source of motion, you can use the shifted exponential distribution which is described by two parameters ( γ , δ > 0):
f ( τ ) = { 0 τ < d γ e γ ( τ d ) τ d
Random variable τ is the time interval between successive packets.
1. Draw a distribution graph (1). What is the relationship between the maximum traffic and δ, for the distribution (#)?
2. Designate a mean value of the distribution (#).
3. Based on measurements of traffic sources ( λ , σ ) select firstly δ parameter for distribution (#), then γ parameter for distribution (#).

Answer & Explanation

Alec Blake

Alec Blake

Expert

2022-07-09Added 11 answers

Part 1 is simple. If δ is the minimum interarrival time for consecutive packets, where time is measured in seconds, then at most 1 / δ packets can arrive in one second. For instance, if δ = 0.01 seconds, meaning that we are assured that the time between packets is at least 0.01 seconds, then the most packets we can observe in one second is 1/0.01=100 packets, and this is σ. So
σ δ = 1.
For Part 3, use what you know from Parts 1 and 2 to establish a relationship between λ and γ. The average traffic intensity λ is simply the average you found in Part 2. Solve for γ in terms of λ and σ.

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