A measurement of the traffic generated by the packet source indicates that the average traffic...





A measurement of the traffic generated by the packet source indicates that the average traffic is λ [packets/s] and maximum traffic is σ [packets/s]. The classic exponential distribution is not appropriate for modeling such a source of traffic, because the exponential distribution contains only one parameter (and two parameters were measured).
To model such a source of motion, you can use the shifted exponential distribution which is described by two parameters ( γ , δ > 0):
f ( τ ) = { 0 τ < d γ e γ ( τ d ) τ d
Random variable τ is the time interval between successive packets.
1. Draw a distribution graph (1). What is the relationship between the maximum traffic and δ, for the distribution (#)?
2. Designate a mean value of the distribution (#).
3. Based on measurements of traffic sources ( λ , σ ) select firstly δ parameter for distribution (#), then γ parameter for distribution (#).

Answer & Explanation

Alec Blake

Alec Blake


2022-07-09Added 11 answers

Part 1 is simple. If δ is the minimum interarrival time for consecutive packets, where time is measured in seconds, then at most 1 / δ packets can arrive in one second. For instance, if δ = 0.01 seconds, meaning that we are assured that the time between packets is at least 0.01 seconds, then the most packets we can observe in one second is 1/0.01=100 packets, and this is σ. So
σ δ = 1.
For Part 3, use what you know from Parts 1 and 2 to establish a relationship between λ and γ. The average traffic intensity λ is simply the average you found in Part 2. Solve for γ in terms of λ and σ.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?