Let f be a (Lebesgue) measurable function defined on <mrow class="MJX-TeXAtom-ORD">

Eden Solomon

Eden Solomon

Answered question

2022-06-24

Let f be a (Lebesgue) measurable function defined on R n . Given a vector x 0 in R n , I would like to know whether the function f ( x + x 0 ) is measurable or not. I know Φ g is measurable whenever Φ is continuous and g is measurable, and a book warns me of an example of a measurable function g and a continuous function Φ such that g Φ is not measurable. However, I have no idea how to prove or disprove measurability of f ( x + x 0 ). Can someone please give me a hand? Thank you very much.

Answer & Explanation

Quinn Everett

Quinn Everett

Beginner2022-06-25Added 23 answers

Let g ( x ) = x + x 0 . E := f 1 ( ( a , ) ) is a measurable set by definition, and g 1 ( E ) = { x x 0 : x E }, i.e. E x 0 . But the translation of a Lebesgue measurable set is Lebesgue measurable, so f g is measurable.
Hailie Blevins

Hailie Blevins

Beginner2022-06-26Added 8 answers

Thank you, and I guess you have used ( f g ) 1 ( ( a , ) ) = E x 0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?