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Averi Mitchell

Averi Mitchell

Answered question

2022-06-07

Let we have ξ which has normal distribution N ( a , σ 2 )
And also let's define η = e ξ . I want to find E η and D η for this random value.
Here's what I've got:
I can find E ξ and D ξ because I know that for ξ:
p ( x ) = 1 2 π σ 2 e ( x a ) 2 2 σ 2
and then we can evaluate that
E ξ = x p ( x )   d x
Same things for disperson and I've got that
D ξ = E ξ 2 E ξ 2 = ( a 2 + σ 2 ) a 2 = σ 2
But how can I use it to evaluate E η and D η ?

Answer & Explanation

ejigaboo8y

ejigaboo8y

Beginner2022-06-08Added 29 answers

If ξ N ( a , σ 2 ), then η = e ξ has a log-normal distribution with:
E ( η ) = e a + σ 2 2
E ( η 2 ) = e 2 a + 2 σ 2
V a r ( η ) = E ( η 2 ) E ( η ) 2 = E ( η ) 2 ( e σ 2 1 ) = e 2 a + σ 2 ( e σ 2 1 )

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