Bergen

2021-02-12

Two independent measurements are made of the lifetime of a charmed strange meson. Each measurement has a standard deviation of $7×{10}^{-15}$ seconds. The lifetime of the meson is estimated by averaging the two measurements.
What is the standard deviation of this estimate ?

Jaylen Fountain

Step 1
It is given that the population standard deviation is $7×{10}^{-15}$.
The lifetime of the meson is estimated by averaging the two measurements.
The standard deviation of the two measurements is obtained by dividing the population standard deviation by square $\sqrt[2]{}$.
Step 2
Thus, the standard deviation of the estimate is, $SD=\frac{7×{10}^{-15}}{\sqrt{2}}=4.9497×{10}^{-15}$.

Do you have a similar question?