tell whether the ordered pair is a solution of the linear system (5,2)2x-3y=42x+8y=11

Subtract the two equations: $2x-$$3y-$$(2x+$$8y)=$$4-$$11$

Remove parentheses: $2x-$$3y-$$2x-$$8y=$$4-$$11$

Cancel one variable: $-$$3y-$$8y=$$4-$$11$

Combine like terms: $-$$11y=$$4-$$11$

Calculate the sum or difference: $-$$11y=$$-$$7$

Divide both sides of the equation by the coefficient of variable: $y=$${\displaystyle \frac{-7}{-11}}$

Rewrite the fraction: $y=$${\displaystyle \frac{7}{11}}$

Substitute into one of the equations: $2x-$$3\times$${\displaystyle \frac{7}{11}}=$$4$

Multiply both sides of the equation by the common denominator: $2x\times$$11-$$3\times$${\displaystyle \frac{7\times 11}{11}}=$$4\times$$11$

Reduce the fractions: $2x\times$$11-$$3\times$$7=$$4\times$$11$
Multiply the monomials: $22x-$$3\times$$7=$$4\times$$11$
Calculate the product or quotient: $22x-$$21=$$44$
Rearrange unknown terms to the left side of the equation: $22x=$$44+$$21$
Calculate the sum or difference: $22x=$$65$
Divide both sides of the equation by the coefficient of variable: $x=$${\displaystyle \frac{65}{22}}$
The solution of the system is:$\left\{\begin{array}{l}x=\frac{65}{22}\\ y=\frac{7}{11}\end{array}\right.$
Answer: $\left\{\begin{array}{l}x=\frac{65}{22}\\ y=\frac{7}{11}\end{array}\right.$