How do you evaluate h(x)=−53|x|+6for x=−2?

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How do you evaluate h(x)=−53|x|+6for x=−2?

patriette65s · Accepted Answer

h(x)=133at x=−2  Explanation:  h(x) is just a way of writing &quot;a function (call it h) in x&quot;, meaning whatever is on the other side of the equation. Given a particular value (-2) you just put it into the equation and solve it.  h(x)=−(53)|x|+6  h(x)=−(106)+6;h(x)=−(106)+366  h(x)=266;h(x)=133 or 4.33

How do you evaluate h(x)=−53|x|+6for x=−2?

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