How do you evaluate 8C2?

jamessinatraaa

jamessinatraaa

Answered

2021-12-27

How do you evaluate 8C2?

Answer & Explanation

autormtak0w

autormtak0w

Expert

2021-12-28Added 31 answers

Explanation:
We have, nCr=n!(nr)!r!
8C2=8!(82)!2!=8!6!2!=6!786!2!=782!=5612=28
Barbara Meeker

Barbara Meeker

Expert

2021-12-29Added 38 answers

In the given problem, we have to evaluate 8C2 Here, we will use the formula of combination which is
nCr=n!(nr)!r! You can easily identify that n is 8 and r is 2 here.
8C2=8!(82)!2!
=8!6!2!
=8×7×6!6!2!
After calculating the above e\times pression, we get
=8×72!
=8×72×1
=562
=28
Therefore, 8C2=28
Vasquez

Vasquez

Expert

2022-01-08Added 457 answers

The formula for a combination of choosing r unique ways from n possibilities is:nCr=n!r!(nr)!where n is the number of items and r is the unique arrangements.Plugging in our numbers of n=8 and r=2, we get:8C2=8!2!(82)!Remember from our factorial lesson that n!=n(n1)(n2)21Calculate the numerato r n!:n!=8!K8!=8×7×6×5×4×3×2×18!=40,320Calculate the first denominator (nr)!:(nr)!=(82)!(82)!=6!=6×5×4×3×2×16!=720Calculate the second denominator r!:r!=22!=2×12!=2Calculate our combination value nCr for n=8 and r=2:8C2=40,3202×7208C2=40,32014408C2=28

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