How do you factor y=x3−2x2+x−2?

Question

alexandrebaud43 · Accepted Answer

(x−2)(x+i)(x−i)  Explanation:  factor the terms by grouping  =x2(x−2)+1(x−2)  take out the common factor (x−2)  =(x−2)(x2+1)  x2+1 can be factored using difference of squares  a2−b2=(a−b)(a+b)  with a=x and b=i⇒(i=−1)  =(x−2)(x+i)(x−i)⇒in factored form

alexandrebaud43 · Accepted Answer

y=(x−2)×(x2+1)  Explanation:  x3−2x2 can be written as x2×(x−2)  y=x2×(x−2)+(x−2)  or  y=x2×(x−2)+1×(x−2)  and bringing the common factor (x−2) to the front, gives the factors:  y=(x−2)×(x2+1)  solving the equation for y=0  gives the solution x=2  meaning that the graph of the equation crosses the x-axis at the point (2,0)  solving the equation for x=0 gives y=−2 , meaning that the graph of the equation crosses the y-axis at (0,-2)  graph {x3−2x2+x−2[−10,10,−5,5]}

RizerMix · Accepted Answer

y=(x2+1)(x−2) Explanation: y=x3−2x2+x−2 We will use a factoring method called grouping. If we group the first and the third and the second and the fourth together, each grout has its own greatest common factor: y=x(x2+1)−2(x2+1) Now we see another CF between the two terms : x2+1 . We can factor it out. y=(x2+1)(x−2)

How do you factor y=x^3−2x^2+x−2?

Answered question

Answer & Explanation

New Questions in Pre-Algebra