 hunterofdeath63

2021-12-18

The number of dimes inside the bag.
Given: A bag contains quarters and dimes in a ratio of 3:5 and there is $6 in quarters in the bag. Answer & Explanation veiga34 Expert 2021-12-19Added 32 answers Calculation: Let the number of dimes in the bag be x. Given that the quarters in the bag make$6. SInce 1 quarter is equivalent to \$0.25, so the total number of quarters in the bag would be,
$\frac{6}{0.25}=24$ quarters
Now given that the ratio of quarters and dimes in the bag is 3:5, so it gives
$\frac{\text{Number of quarters}}{\text{Number of dimes}}=\frac{3}{5}$
$\frac{24}{x}=\frac{3}{5}$
$24×5=3×x$
$120=3x$
$x=\frac{120}{3}$
$x=40$
Thus, there are 40 dimes inside the bag. Bubich13

Expert

Step 1
Given: $\frac{6}{0.25}=24$ quarters
The formula: $\frac{\text{Number of quarters}}{\text{Number of dimes}}=\frac{3}{5}$
$\frac{24}{x}=\frac{3}{5}$
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5x, the least common multiple of x,5.
$5×24=3x$
Multiply 5 and 24 to get 120.
$120=3x$
Swap sides so that all variable terms are on the left hand side.
$3x=120$
Divide both sides by 3.
$x=\frac{120}{3}$
Divide 120 by 3 to get 40.
$x=40$ nick1337

Expert

Step 1
For the equation
$\frac{24}{x}=\frac{3}{5}$
The cross product is
$25×5=x×3$
Solving for x
$x=\frac{24×5}{3}$
And reducing
x=40

Do you have a similar question?