Bevan Mcdonald

2021-01-02

Evaluate the expression $\frac{\sqrt{-6}}{\sqrt{-3}\sqrt{-4}}$ and write the result in the form a+bi

odgovoreh

$i\frac{\sqrt{6}}{i\sqrt{3}\cdot i\sqrt{4}}=-i\frac{\sqrt{6}}{2}\sqrt{3}=-i\frac{\sqrt{\frac{6}{3}}}{2}=-i\frac{\sqrt{2}}{2}$.

So $a=0\phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}b=-\frac{\sqrt{2}}{2}$ for a+ib.
Therefore before rationalisation.

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