Sydney Shaffer

2023-03-13

Factorise ${x}^{2}-4x-5$

Quentin Lester

Factorizing the polynomial:
${x}^{2}-4x-5\phantom{\rule{0ex}{0ex}}={x}^{2}-5x+x-5\phantom{\rule{0ex}{0ex}}=x\left(x-5\right)+1\left(x-5\right)\phantom{\rule{0ex}{0ex}}=\left(x-5\right)\left(x+1\right)$
Hence, the factors of the given polynomial ${x}^{2}-4x-5$ are $\left(x-5\right)$ and $\left(x+1\right)$

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