Find the smallest Number which leaves remainder 8 and 12 when divided by 28 and 32 respectively

Lucille Li

Lucille Li

Answered question

2023-02-06

Find the smallest Number which leaves remainder 8 and 12 when divided by 28 and 32 respectively

Answer & Explanation

Leticia Robertson

Leticia Robertson

Beginner2023-02-07Added 8 answers

We are asked to find the smallest number that, when divided by certain numbers, leaves some remainders.
Follow these steps to find the smallest number:
1) Subtract the remainders from the given numbers:
28-8 = 20
32 -12 = 20
Both of them give 20
2) Find the LCM of 28 and 32
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
LCM = 2 × 2 × 2 × 2 × 2 × 7 = 224
3) Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32 = LCM -20 = 224 - 20 = 204
So answer is 204

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