# Get integral calculus homework help

Recent questions in Integral Calculus
Mary Reyes 2022-01-21 Answered

### Second derivative using implicit differentiation with respect to x of $$\displaystyle{x}={\sin{{y}}}+{\cos{{y}}}$$ $$\displaystyle{1}={\cos{{y}}}{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}-{\sin{{y}}}{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}$$ $$\displaystyle{1}={\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}{\left({\cos{{y}}}-{\sin{{y}}}\right)}$$ $$\displaystyle{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}={\frac{{{1}}}{{{\cos{{y}}}-{\sin{{y}}}}}}$$

Arthur Pratt 2022-01-20 Answered

### Does ODE initial value problem produce beat or resonance phenomenon? $$\displaystyle{x}{''}+{9}{x}={\sin{{\left({3}{t}\right)}}}$$ $$\displaystyle{x}{\left({0}\right)}={x}'{\left({0}\right)}={0}$$. We are allowed to solve differential equations with TI-89.

Carol Valentine 2022-01-20 Answered

### How to solve $$\displaystyle{x}'{\left({t}\right)}={\frac{{{x}+{t}}}{{{2}{t}-{x}}}}$$?

Mary Buchanan 2022-01-20 Answered

### Solving simple differential equation $$\displaystyle{\left({t}+{4}\right)}{\left.{d}{x}\right.}={4}{\left({1}+{x}^{{{2}}}\right)}{\left.{d}{t}\right.}$$

veksetz 2022-01-20

### How to solve $$\displaystyle{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}={5}{x}{y}+{\sin{{x}}}$$? With $$\displaystyle{y}{\left({0}\right)}={1}$$. Use an integrating factor.

Pam Stokes 2022-01-20 Answered

### $$\displaystyle{y}_{{{1}}},{y}_{{{2}}},{y}_{{{3}}}$$ are particular solutions of $$\displaystyle{y}'+{a}{\left({x}\right)}{y}={b}{\left({x}\right)}$$, so the function $$\displaystyle{\frac{{{y}_{{{2}}}-{y}_{{{3}}}}}{{{y}_{{{3}}}-{y}_{{{1}}}}}}$$ is constant.

Helen Lewis 2022-01-20 Answered

### What might be a solution to the differential equation of the form $$\displaystyle{x}{y}{''}={c}{\frac{{{y}}}{{{y}+{d}}}}$$ where $$\displaystyle{y}={y}{\left({x}\right)}$$ and c,d are constants? I am supposed to simply ''state'' a solution to this, but I don;t think it is all that obvious.

Mary Jackson 2022-01-20 Answered

### I was reading some of my notes and I was not sure how the following works: $$\displaystyle{\frac{{{d}^{{{2}}}{y}}}{{{\left.{d}{x}\right.}^{{{2}}}}}}+{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}={0}$$ Solve the above with the condition $$\displaystyle{y}{\left({0}\right)}={0}$$ $$\displaystyle\Rightarrow{y}{\left({x}\right)}={A}{\left({1}-{e}^{{-{x}}}\right)}$$ with A an arbitrary constant. I was just wondering how do you solve the above to get $$\displaystyle{y}{\left({x}\right)}={A}{\left({1}-{e}^{{-{x}}}\right)}$$? Because when I tried it, I got: $$\displaystyle{y}={A}+{B}{e}^{{-{x}}}$$, and using the condition $$\displaystyle{y}{\left({0}\right)}={0}$$, I got $$\displaystyle{A}+{B}={0}$$.

Michael Maggard 2022-01-20 Answered