Let:

\(y=2x−3\) (1)

\(5x+y=11\) (2)

Solve by substitution. Substitute (1) to (2) and solve for x:

\(5x+(2x−3)=11\)

\(7x−3=11\)

\(7x=14\)

\(x=2
\)

Solve for yy using (1):

\(y=2(2)−3\)

\(y=1\)

So, the solution of the system is:

\((2,1)\)

which is choice A.