Let A =&nbsp; 1 &nbsp; 2 &nbsp; &nbsp; 0 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Find&nbsp; AAt&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;3 &nbsp; -1 &nbsp;4

To find the matrix product AAt, we need to multiply matrix A by its transpose.The given matrix A is:A=[1203−14]To find A transpose, we simply interchange the rows and columns of A:AT=[132−104]Now, we can proceed to calculate the matrix product AAt by multiplying A by its transpose.AAt=A·ATAAt=[1203−14]·[132−104]To compute each element of the resulting matrix, we perform row-by-column multiplications and add the products.AAt=[(1·1)+(2·2)+(0·0)(1·3)+(2·−1)+(0·4)(3·1)+(−1·2)+(4·0)(3·3)+(−1·−1)+(4·4)]Simplifying the multiplications:AAt=[1+4+03−2+03−2+09+1+16]AAt=[51126]Therefore, the matrix AAt is:AAt=[51126]