An aeroplane accelerates down a runway at 3.20 m / s 2 for 32.8 seconds until lifts off from the ground. How far did you travel before takeoff?

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An aeroplane accelerates down a runway at   3.20     m      /        s    2   for 32.8 seconds until lifts off from the ground. How far did you travel before takeoff?

Garagozzodgc · Accepted Answer

Step 1: Given that:The acceleration(a) in the aeroplane =   3.20  m      s          −      2       Time taken(t) until lift off = 32.8sec Initial velocity(u) of the aeroplane = 0Step 2: calculating the distance flown by an airplane before takeoff:According to the second equation of motion;  s  =  u  t  +  1      /    2  a      t    2   Where s = distance travelled            u = Initial velocity             t = Time             a = accelerationPutting the values, we get;  s  =  0  ×  32.8  s  e  c  +  1      /    2  ×  3.2  m      s          −      2        ×  (  32.8  s  e  c      )    2      s  =  1.6  ×  32.8  ×  32.8    s  =  1.6  ×  1075.84    s  =  1721.344    s  ≈  1721.3  m Thus,The distance covered by the aeroplane before takeoff is 1721.3m .

An aeroplane accelerates down a runway at 3.20 m/s^2 for 32.8 seconds until lifts off from the ground. How far did you travel before takeoff?

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