zgribestika

## Answered question

2022-01-15

Arrange these species by their ability to act as an oxidizing agent.
Best oxidizing agent
Poorest oxidizing agent

### Answer & Explanation

censoratojk

Beginner2022-01-16Added 46 answers

Step 1
Given ionic species:

Step 2
From the standard reduction potential data
$N{i}^{2+}+2{e}^{-}⇒Ni$
${E}^{\circ }=-0.26v$
$M{g}^{2+}+2{e}^{-}⇒Mg$
${E}^{\circ }=-2.37v$
$Z{n}^{2+}+2{e}^{-}⇒Zn$
${E}^{-}=-0.76v$
$A{u}^{3+}+3{e}^{-}⇒Au$
${E}^{\circ }=1.40v$
Reduction potential more act as strong oxidining agent means it
Can take electrons from less reducetion potentid species
Based on this: best oxiding agent is $A{u}^{3+}$
Poor oxiding agent: $M{g}^{2+}$
Oxidizing agent Capacity increasing order $M{g}^{2+}
Best oxidizing agent
$A{u}^{3+}$
$N{i}^{2+}$
$Z{n}^{2+}$ Poor oxigizing agent $M{g}^{2+}$

jgardner33v4

Beginner2022-01-17Added 35 answers

Solution:

Oxidizing agent capacity increasing order:
$M{g}^{2+}

alenahelenash

Skilled2022-01-23Added 366 answers

Solution from given: then $\left(1x+5\right)=\left(4x+1\right)$ $\left\{\text{the qualioy of parallelegram}\right\}$ $-1x=-4$ $x=2$ then $PQ=2x+5=2×2+5=9cm$

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