A thin, horizontal, 11-cm-diameter copper plate is charged to -2.9 nC. Assume that the electrons...

Mary Jackson

Mary Jackson

Answered

2022-01-15

A thin, horizontal, 11-cm-diameter copper plate is charged to -2.9 nC. Assume that the electrons are uniformly distributed on the surface
What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?
Answer: 1.7104NC
What is the direction of the electric field 0.1 mm above the center of the top surface of the plate?
Answer: toward the plate
What is the strength of the electric field at the plates

Answer & Explanation

Jim Hunt

Jim Hunt

Expert

2022-01-16Added 45 answers

Step 1 strength of electric field
Strength of electric field is calculated using charge density. It is defined as the charge contained over a surface area.
Charge density=Chargesurface area
Electric field intensity=charge density2ξ0
Where, ξ0=8.85×1012Fm
Step 2 calculate electric field strength
1.strength of electric field above the center of top surface is
Charge density is,
σ=2.9×109π×(0.055)2
σ=3.08×107Cm2
for distance 0.1 mm is very small compared to plates diameter. So assuming plate as infinite sheet of charge.
Strength of electric field,
E=σ2ξ0
E=3.08×1072×8.85×1012
E=1.74×106NC
2. negative sign indicates that direction of field is towards the sheet.
3. Net charge on the center of mass of plate is zero, so electric field is zero and so, is the strength of electric field.
E=0NC
4. Strength of electric field 0.1 mm below is just the same as above the top surface of plate.
As copper is a conductor, it distributes charge itself across it, E=1.74×104NC
5. Direction of field remains same below the plate
Juan Spiller

Juan Spiller

Expert

2022-01-17Added 38 answers

Step 1
Given data:
Diameter of the copper plate, d=14cm=0.14m
Charge, Q=2.8nC=2.8×109C
Distance, x=0.1mm=0.1×103m
Step 2
To determine:
C. Electric field strength at the plates
alenahelenash

alenahelenash

Expert

2022-01-23Added 366 answers

Complete Question A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate? Answer: The values is E=248.2N/C Explanation: From the question we are told that. The diameter is d=12cm=0.12m The distance from the center is k=0.1mm=1104m Generally the radius is mathematically represented as r=d2 r=0.122 r=0.06m Generally electric field is mathematically represented as E=Q2ξ0[1kr2+k2] substituting values E=4.41092(8.851012)[1(1.00104)(0.06)2+(1.0104)2] E=248.2N/C

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