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burkinaval1b

Answered

2022-01-16

Prove the identity.

$\mathrm{sin}4x=2\mathrm{sin}2x\mathrm{cos}2x$

Answer & Explanation

zurilomk4

Expert

2022-01-17Added 35 answers

Work on the left side.

Write 4x as 2*2x:

$\mathrm{sin}4x=\mathrm{sin}(2\cdot 2x)$

Use the double-angle identity for sine$\mathrm{sin}2u=2\mathrm{sin}u\mathrm{cos}u$ where u=2x:

$\mathrm{sin}4x=2\mathrm{sin}2x\mathrm{cos}2x$

Result:

Hint: Write 4x as 2*2x and use the double-angle identity for sine.

Write 4x as 2*2x:

Use the double-angle identity for sine

Result:

Hint: Write 4x as 2*2x and use the double-angle identity for sine.

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