Prove the identity. sin⁡4x=2sin⁡2xcos⁡2x

burkinaval1b

burkinaval1b

Answered

2022-01-16

Prove the identity.
sin4x=2sin2xcos2x

Answer & Explanation

zurilomk4

zurilomk4

Expert

2022-01-17Added 35 answers

Work on the left side.
Write 4x as 2*2x:
sin4x=sin(22x)
Use the double-angle identity for sine sin2u=2sinucosu where u=2x:
sin4x=2sin2xcos2x
Result:
Hint: Write 4x as 2*2x and use the double-angle identity for sine.

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