keche0b

2022-01-16

1) For the combination of resistors shown, find the equivalent resistance between points A and B.

2) For the set-up shown, find the equivalent resistance between points A and B.

soanooooo40

Step 1
The expression for equivalent resistance of the resistor connected in series is,
$Req={R}_{1}+{R}_{2}+{R}_{3}$
$=2\mathrm{\Omega }+3\mathrm{\Omega }+4\mathrm{\Omega }$
$=9\mathrm{\Omega }$
Step 2
For parallel connection
$\frac{1}{Req}=\frac{1}{{R}_{1}}+\frac{1}{{R}_{2}}+\frac{1}{{R}_{3}}$
$⇒Req=\frac{{R}_{1}{R}_{2}}{{R}_{1}+{R}_{2}}=\frac{6\mathrm{\Omega }×3\mathrm{\Omega }}{6\mathrm{\Omega }+3\mathrm{\Omega }}$
$⇒Req=\frac{9\mathrm{\Omega }×2\mathrm{\Omega }}{9\mathrm{\Omega }}$
$⇒Req=2\mathrm{\Omega }$

Andrew Reyes

Step 1
Solution:
1) Equivalent resistance $=2+3+4=9ohm$
2) Equivalent resistance $=\frac{6×3}{6+3}=\frac{18}{9}=2ohm$

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