Silver chloride, often used in silver plating, contains 75.27% Ag. Calculate the mass of silver...

Step 1
The given mass of pure silver is converted into grams.
Given, 245mg of pure Ag
${\displaystyle 1g=1000g}$
${\displaystyle =245mg\times \frac{1g}{1000mg}}$
${\displaystyle =0.245g}$
Step 2
The mass of silver chloride required to plate 245mg pure silver is calculated as
Consider, x grams of AgCl contains 0.245g of pure Ag.
Given, AgCl contains 75.27% Ag
then, ${\displaystyle x\times \frac{75.27}{100}=0.245g}$
${\displaystyle x=\frac{0.245\times 100}{75.27}=0.325g}$
Conversion of gram into milligram
${\displaystyle 0.325\times \frac{1000mg}{1g}=325mg}$ AgCl
Step 3
The mass of silver chloride required to plate 245mg pure silver is 325mg.

Help me please. I need this answer to a chemistry problem. Calculate the mass of silver chloride required to make the plate. Thank you.