A scalloped hammerhead shark swims at a steady speed of 1.0 m/sm/s with its 83...

Step 1
Given:
The velocity of hammerhead shark ${\displaystyle \left(v\right)=1.0\frac{m}{s}}$
Length of hammerhead ${\displaystyle \left(L\right)=83cm}$.
the magnetic field of the earth ${\displaystyle \left(B\right)=52\mu T}$
the angle between the hammerhead and the earth's magnetic field ${\displaystyle ={90}^{\circ }}$.
Step 2
the magnitude of electromotive force is given by,
${\displaystyle F_{emf}=BL\times v}$
${\displaystyle F_{emf}=BLv\sin \theta }$
${\displaystyle F_{emf}=52\times {10}^{-6}\times 83\times {10}^{-2}\times 1}$
${\displaystyle F_{emf}=4.316\times {10}^{-5}N}$
Step 3
Answer:
electromotive force ${\displaystyle =4.316\times {10}^{-5}N}$

Given:
- The speed of scalloped hammerhead shark is: ${\displaystyle v_a=1.0\frac{m}{s}}$.
- The width of head is: ${\displaystyle w_a=83cm=0.83m}$.
- The magnetic field is: ${\displaystyle B_a=52\mu T=53\times {10}^{-6}T}$.
The expression for the change in area through which magnetic field moves is,
${\displaystyle \mathrm{△}{A}_a=\mathrm{△}{l}_a{w}_a}$
Here ${\displaystyle \mathrm{△}{l}_a\text{and}{w}_a}$ are change in length and width respectively.
The expression for the speed of scalloped hammerhead shark is,
${\displaystyle v_a=\frac{\mathrm{△}{l}_a}{\mathrm{△}t}}$
Here ${\displaystyle \mathrm{△}}$ is time interval.
The expression for the magnetic flux is,
${\displaystyle \mathrm{△}{\varphi }_a=B_a\mathrm{△}{A}_a}$
The expression for the induced emf by using the Faradays

Answer: $7.4\times {10}^{-5}T$. Explanation: Emf induced $=BLv$ Where B is magnetic field , L is length of rod or any other object moving in magnetic field and v is velocity of moving rod. Here $B=56\times {10}^{-6}T$ $L=88\times {10}^{-2}m$ $v=1.5m/s$ emf induced $=56\times {10}^{-6}\times 88\times {10}^{-2}\times 1.5$ $=7.4\times {10}^{-5}T$.