William Burnett

2022-01-12

Both $HC{O}_{\left\{3\right\}}^{-}$ and $H{S}^{-}$ are amphoteric. Write an equation to show how each substance can act as an acid and another equation to show how each can act as a base.

Ronnie Schechter

Expert

$HC{O}_{3}^{-}\left(ag\right)+HS\left(ag\right)⇌C{O}_{3}^{2-}\left(ag\right)+{H}_{2}S\left(aq\right)$
Let $HC{O}_{\left\{3\right\}}^{-}$ be a $Br\mathrm{\varnothing }$ nsted-Lowry acid and let $H{S}^{-}$ be a $Br\mathrm{\varnothing }$ nsted-Lowry base. The conjugate base of the acid is then determined by removing an H atom and
a unit of positive charge. The conjugate acid of the base is then determined by adding an H atom anda unit of positive charge.
$HC{O}_{3}^{-}\left(ag\right)+H{S}^{-}\left(ag\right)⇌{H}_{2}C{O}_{3}\left(ag\right)+{S}^{-2}\left(aq\right)$
Let $HC{O}_{\left\{3\right\}}^{-}$ be a ​​​​​​​$Br\mathrm{\varnothing }$ nsted-Lowry base and let $H{S}^{-}$
be a $Br\mathrm{\varnothing }$ nsted-Lowry acid. The conjugate acid of the
base is then determined by adding an H atom anda unit of positive charge. The conjugate base of the acid is then determined by removing an H atom and a unit of positive charge.

soanooooo40

Expert

Explanation:
According to Bronsted and Lowry an acid is a proton donor and base is a proton acceptor.
Therefore, the equation for the reaction will be as follows.
$HC{O}_{3}^{-}+H{S}^{-}={H}_{2}C{O}_{3}+{S}^{2}t$
Here, $HC{O}_{\left\{3\right\}}^{-}$ acts as a base as it is accepting a proton and $H{S}^{-}$ acts as an acid because it is donating a proton.

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