A ball is thrown vertically upward with an initial velocity of 96 feet per second.The...

Sapewa

Sapewa

Answered

2022-01-09

A ball is thrown vertically upward with an initial velocity of 96 feet per second.The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t16t2

(a) At what time t will the ball strike the ground? 

(b) For what time t is the ball more than 128 feet above the ground?

Answer & Explanation

Bukvald5z

Bukvald5z

Expert

2022-01-10Added 33 answers

We have a ball is thrown vertically upward with an initial velocity of 96 feet per second.The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t16t2


a) we have s(t)=96(t)16t2=0 
since the distance from the ground is s(t) so we have 
s(t)=96t16t2=0 
t(9616t)=0 
t=0 or t=6 
the ball is on the ground at t=0 seconds and t=6 seconds when the ball is thrown and when the ball lands. 
So, the ball strikes the ground after 6 seconds.

Ella Williams

Ella Williams

Expert

2022-01-11Added 28 answers

b) when is s=128 so putting this value in the function then we have 
128=96t16t2 
t26t+8=0 
(t4)(t2)=0 
that is between 2 seconds and 4 seconds.

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