How many atoms are in 1.75 mol CHCl3

Step 1 
${\displaystyle 1mol=6.022\times {10}^{23}}$ atoms 
To determine the number of atoms, dimly multiply the number of moles by ${\displaystyle 6.022\times {10}^{23}}$ or Avogadros

Step 1
To find the number of atoms in any quantity of moles you just need to multiply the number of, moles times Avogadro's constant.
Which will gives the number of molecules, and then multiply by the number of atoms is one molecule which is
${\displaystyle 5(C,H,\text{and}3Cl)}$.
The calculus is ${\displaystyle 1.75mol\times 6.02\times {10}^{23}}$ $\frac{molecules}{mol}\times 5\frac{atoms}{molecule}$
${\displaystyle =52.675\times {10}^{23}a\to ms}$
${\displaystyle =5.2675\times {10}^{24}}$ atoms.

$1mol=6.022\times {10}^{23}$ (atoms or molecules)
1.75 moles of $(CHC{l}_3)$ we have: $1.75moles\times (6.022\times {10}^{23}molecules)=1.05385\times {10}^{25}$ molecules.
a molecule of $CHC{l}_3$ have, 1 atom of C, 1 atom of H, and 3 atoms of Cl, therefore a molecule of $CHC{l}_{3}have1atom+1atom+3atom=5atoms.$
Therefore:
$\begin{array}{}1molecule(CHC{l}_3)\cdots 5atoms\\ 1.058385\times {10}^{23}molecules(CHC{l}_3)\cdots x\\ x=\frac{1.058385\times {10}^{24}molecules\times 5atoms}{1molecule}\approx 5.26925\times {10}^{24}atoms\end{array}$
Solution: $=5.269\times {10}^{24}$ atoms.