Two sites are being considered for wind power generation. In the first

Step 1
Givens:
${\displaystyle V_1=7\frac{m}{s}}$
${\displaystyle {\text{Operation time}}_1=3000}$ hours per year
${\displaystyle V_2=10\frac{m}{s}}$
${\displaystyle {\text{Operation time}}_2=1500}$ hours per year
Solution:
Note: The wind blows streadly. So, ${\displaystyle \dot{KE}=\left(\dot{0.5m{V}^2}\right)=\dot{m}\times 0.5V^2}$
The power generation is the time rate of kinetic energy, which can be calculated as follows,
Power ${\displaystyle =\mathrm{\Delta }\dot{KE}=\dot{m}\frac{V^2}{2}}$
Regarding that ${\displaystyle \dot{m}\propto V}$. Then,
Power ${\displaystyle \propto V^3\Rightarrow }$ Power ${\displaystyle =const\times V^3}$
Since ${\displaystyle {\rho }_a}$ is constant for both sites and Area is the same as same wind turbine is use turine is used.
For the first site,
${\displaystyle {\text{Power}}_1=const.\times V_1^3=const.\times 343W}$
For the second site,
${\displaystyle {\text{Power}}_2=cont.\times V_2^3=const.\times 1000W}$
Calculating energy generation per year for each of the two sites.
${\displaystyle E_{year}=Power\times \text{Operation time per year}}$
For the first site,
$E_{year,1}=Powe{r}_1\times \text{Operation time\_1}=const.\times 343\times 3000=const.\times 1029000(W\cdot \frac{hour}{year})$
For the second site,
${\displaystyle E_{year,2}=Powe{r}_2\times {\text{Operation time}}_2=const.\times 1000\times 1500=const.\times 1500000(W\cdot \frac{hour}{year})}$
${\displaystyle \therefore E_{year,2}>E_{year,1}}$ (i.e. Second site is better)

Step 1
Explanation:
$\begin{array}{}\\ V_1=7\frac{m}{s}\\ Tim{e}_1=3000\frac{hours}{year}\\ V_2=10\frac{m}{s}\\ Tim{e}_2=1500\frac{hours}{year}\end{array}$
The power generation is the time rate of kinetic energy which can be calculated as:
Powert $=\mathrm{\Delta }KE=m\times \frac{V^2}{2}$
Regarding that $m\propto V$ Then
Power $\propto V^3\Rightarrow Power=constant\times V^3$
Since $\rho a$ is constant for both sides and Area is the same as same wind turbine is used
For First site
$Powe{r}_1=const.V^3$
$Power{t}_1=const.(7\frac{m}{s}{)}^3$
$Powe{r}_1=const.343Watt$
For second side
$Powe{r}_2=const.V_2^3$
$Powe{r}_2=conts.(10\frac{m}{s}{)}^3$
$Powe{r}_2=const.1000W$
Calculating energy generation per year for each of two sites
$E_{year}=Power\times \text{Operation time per year}$
For First site
$E{.}_{year1}=Powe{r}_1\times \text{Operation}tim{e}_1\text{per year}$
$E_{year1}=const.\times 343W\times 3000$
$E_{year1}=const.10290000(W.\frac{hour}{year})$
For Second site
$E_{year1}=Powe{r}_1\times \text{Operation}tim{e}_2\text{per year}$
$E_{year2}=const.\times 1000W\times 1500$
$E_{year2}=const.1500000(W.\frac{hour}{year})$
So,
$E_{year2}>E_{year1}$ (Second site is better)