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Walter Clyburn Answered2022-01-03

Rachel has good distant vision but has a touch of presbyopia. Her near point is 0.60 m. When she wears +2.0 D reading glasses, what is her near point? Her far point?

Answer & Explanation

Bertha Jordan Expert2022-01-04Added 37 answers

Given Power =+2D Initial near point =0.6m a) power

(P) = \frac{1}{f} = + 2 D, V = - 0.6 m

Here, using the lens equation as following below,

\frac{1}{V} - \frac{1}{u} = \frac{1}{f}

- \frac{1}{0.6} - \frac{1}{u} = 2

u = - 0.27 m

Her near point is 0.27 m
b) Now, her new near point

V = \infty

P = \frac{1}{f}

2 = \frac{1}{f}

f = \frac{1}{2} m

f = 0.5 m

Now, using the lens equation,

\frac{1}{V} - \frac{1}{u} = \frac{1}{f}

\frac{1}{\infty} - \frac{1}{u} = \frac{1}{0.5}

u = - 0.5 m

Raches far point is 0.5 m

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