Suppose y=2x+1 where x and y are functions of t. (a) if dxdt=3,finddydtwhen x=4. (b)...

Sandra Allison

Sandra Allison

Answered

2021-12-22

Suppose y=2x+1 where x and y are functions of t.
(a) if dxdt=3,finddydtwhen x=4.
(b) if dydt=5, find dxdt when x=12.

Answer & Explanation

SlabydouluS62

SlabydouluS62

Expert

2021-12-23Added 52 answers

Given that y=2x+1
x and y are functions of t.
a) dxdt=3
To find dydt3 when x=4
y=2x+1
dydt=dydxdxdt
=122x+12dxdt
=12x+13
=324+1 at x=4
=39
=33
=1
So dydt=1 at x=4
Ronnie Schechter

Ronnie Schechter

Expert

2021-12-24Added 27 answers

b) Given that dydt=5. To find dxdt when x=12
y=2x+1
y2=2x+1 (On squaring both sides)
x=12(y21)
dxdt=12(2y)=y
dxdt=dxdydydt
=ydydt
=55 (when x=12 we get y=212+1=25=5)
=25
So dxdt=25
user_27qwe

user_27qwe

Expert

2021-12-30Added 230 answers

Very helpful! I used it to solve a similar problem.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?