Square root inside a square root
Hi guys I just want to ask how to solve this.
The given is:
then solve for the
then it becomes.
Can the expression be simplified?
Answer & Explanation
As we have the unwritten index 2 for the sqare root, we multiply it by the index of the root inside the first root.
Another example is:
The nth root of a number a:
The square root of the square root of x is therefore
Since the domain of
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