Kaspaueru2

Answered

2021-12-25

Square root inside a square root

Hi guys I just want to ask how to solve this.

The given is:

then solve for the

then it becomes.

Can the expression be simplified?

Answer & Explanation

vicki331g8

Expert

2021-12-26Added 37 answers

Answer:

$\sqrt{x}={x}^{\frac{1}{2}}$

$\sqrt{\sqrt{x}}={\left({x}^{\frac{1}{2}}\right)}^{\frac{1}{2}}={x}^{\frac{1}{4}}=\sqrt{4}\left\{x\right\}$

Rita Miller

Expert

2021-12-27Added 28 answers

As we have the unwritten index 2 for the sqare root, we multiply it by the index of the root inside the first root.

Another example is:

karton

Expert

2021-12-30Added 439 answers

The nth root of a number a:

The square root of the square root of x is therefore

Since the domain of

Most Popular Questions