Suppose that one of Millikan’s oil drops has a charge of −4.8×10−19 C. How many...

gorovogpg

gorovogpg

Answered

2021-12-25

Suppose that one of Millikan’s oil drops has a charge of 4.8×1019 C. How many excess electrons does the drop contain?

Answer & Explanation

Lynne Trussell

Lynne Trussell

Expert

2021-12-26Added 32 answers

Given,
One Milikian's oil drop has a charge =4.8×1019 C
Charge of an electron =1.6×1019
Number of electrons can be calculated as:
Charge=no.of electrons×charge of an electron
No. of electrons=Chargecharge of an electron
No. of electrons=4.8×1019 C1.6×1019 C=3
Answer:
Number of excess electrons the drop contain =3

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