gorovogpg

2021-12-25

Suppose that one of Millikan’s oil drops has a charge of $-4.8×{10}^{-19}$ C. How many excess electrons does the drop contain?

Lynne Trussell

Expert

Given,
One Milikian's oil drop has a charge $=-4.8×{10}^{-19}$ C
Charge of an electron $=-1.6×{10}^{-19}$
Number of electrons can be calculated as:
$\text{Charge}=\text{no.of electrons}×\text{charge of an electron}$
$\text{No. of electrons}=\frac{\text{Charge}}{\text{charge of an electron}}$