The fastest measured pitched baseball left the pitcher’s hand at a spe

Pamela Meyer

Pamela Meyer

Answered question

2021-12-24

The fastest measured pitched baseball left the pitcher’s hand at a speed of 45.0 m/s. If the pitcher was in contact with the ball over a distance of 1.50 m and produced constant acceleration, (a) what acceleration did he give the ball, and (b) how much time did it take him to pitch it?

Answer & Explanation

Juan Spiller

Juan Spiller

Beginner2021-12-25Added 38 answers

a) This is the analysis model particle under constant acceleration.
vξ=0
In order to calculate the acceleration, we will use the following equation:
vxf2=vξ22ax(xfxi)
452=0+2ax(1.50)
ax=675 ms2
b) We can calculate the time from the following equation:
vxf=vxi+axt
45=0+675t
t=0.067 s

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