kramtus51

2021-12-26

Curling is a sport played with 20 kg stones that slide across an ice surface. Suppose a curling stone sliding at 1 m/s strikes another, stationery stone and comes to rest in 2 ms. Approximately how much force is there on the stone during the impact? A. 200 N B. 1000 N C. 2000 N D. 10,000 N

Lakisha Archer

Expert

Givens:

$J=\mathrm{△}p=m{v}_{f}-m{v}_{i}$
$F\mathrm{△}t=m{v}_{f}-m{v}_{i}$
$F=\frac{m{v}_{f}-m{v}_{i}}{trainglet}=\frac{0-\left(20×1.0\right)}{2×{10}^{-3}}=\frac{-20}{2×{10}^{-3}}$

Notice, the negative sign becaus the force is opposing the velocity of the stone
Result: Choise D

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