In the theory of relativity, the mass of a particle with velocity v is m=m01−v2c2...

Maria Huey

Maria Huey

Answered

2021-12-26

In the theory of relativity, the mass of a particle with velocity v is
m=m01v2c2
where m0 is the mass of the particle at rest and c is the speed of light. What happens as vct?

Answer & Explanation

William Appel

William Appel

Expert

2021-12-27Added 44 answers

limvcm01v2c2=
Since v is close to c and v<cv2<c2v2c2<1
The direction of the inequality does not change because v and c are the speed of the velocity of the particle and the velocity of light, respectively. The magnitude of a vector is always a positive number.
v2c21 (multiplying both sides by -1)
1v2c2>0 the denominator is a small and positive number.
The numerator m0 is a positive number
The division is then a huge positive number.

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