Carla Murphy

2021-12-16

A 2.0 kg , 20-cm-diameter turntable rotates at 130 rpm on frictionless bearings. Two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.

What is the turntables

What is the turntables

MoxboasteBots5h

Beginner2021-12-17Added 35 answers

Put the values of the question in writing.

$M=2\text{}kg$

$\omega =130\text{}r\pm$

$m=510\text{}g$

$=0.510\text{}k$

Moment of inertia of 2 kf rotating block.

$I=\frac{1}{2}M{R}^{2}$

Block with a 510g moment of inertia.

$I}^{\prime}=\frac{1}{2}m{r}^{2$

Determine the 510 g block's angular moment with respect to the 2 kg block's rotating center.

$I}^{\prime}{\omega}^{\prime}=(1+2m{r}^{2}){\omega}^{\prime$

Calculate a turntable's angular velocity.

No external torque was generated in the situation discussed above, keeping the angular moment constant.

$I\omega ={I}^{\prime}{\omega}^{\prime}$

$I\omega =(I+2m{r}^{2}){\omega}^{\prime}$

$\frac{m{R}^{2}}{2}\times \omega =(I+2m{r}^{2})\times {\omega}^{\prime}$

$\frac{2\times {0.1}^{2}}{2}\times 130=(\frac{2\times {0.1}^{2}}{2}+2\times 0.510\times {0.1}^{2})\times {\omega}^{\prime}$

${\omega}^{\prime}=64.35\text{}r\pm$

22+64

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