A 2.0 kg , 20-cm-diameter turntable rotates at 130 rpm on frictionless bearings. Two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntables

Question

A 2.0 kg ,  20-cm-diameter turntable rotates at 130 rpm on frictionless bearings. Two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.  What is the turntables

MoxboasteBots5h · Accepted Answer

Put the values of the question in writing.M=2&amp;nbsp;kgω=130&amp;nbsp;r±m=510&amp;nbsp;g=0.510&amp;nbsp;kMoment of inertia of 2 kf rotating block.I=12MR2Block with a 510g moment of inertia.I′=12mr2Determine the 510 g block&#039;s angular moment with respect to the 2 kg block&#039;s rotating center.I′ω′=(1+2mr2)ω′Calculate a turntable&#039;s angular velocity.No external torque was generated in the situation discussed above, keeping the angular moment constant.Iω=I′ω′Iω=(I+2mr2)ω′mR22×ω=(I+2mr2)×ω′2×0.122×130=(2×0.122+2×0.510×0.12)×ω′ω′=64.35&amp;nbsp;r±

A 2.0 kg , 20-cm-diameter turntable rotates at 130 rpm on frictionles

Answered question

Answer & Explanation

New Questions in Other