Find the absolute extrema of the function on the closed

lilyta79jd

lilyta79jd

Answered question

2021-11-14

Find the absolute extrema of the function on the closed interval.
y=3x232x,[1,1]

Answer & Explanation

Ourst1977

Ourst1977

Beginner2021-11-15Added 21 answers

y=3x232x,[1,1]
So, Critical number:
y=3x232x
diffirentiate to x
y=32xx132
y=2x132
y=2x132
Put y'=0
2x132=0
2x13=2
1x13=1
1=x13
13=x
1=x
x=1
Considering boundary numbers and critical numbers, we have the following numbers:
x=1 and x=1
f(x)=y=3x232x
f(1)=3(1)232(1)
=3(1)+2
=5
f(1)=3(1)232(1)
=32
=1
f(1)=5 absolute maximum
f(1)=1 absolute minimum

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