A 60kg skier with an initial speed of 12 m/s coasts up a 2.5 m high rise that makes an angle of 35∘ with the horizontal. a) if the coefficient of friction between the skis and the snow is 0.08, find the speed when he reaches the top of the rise. b) how much work does friction do on the skier?

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Part A  First calculate the acceleration  a=g(sin⁡0+μcos⁡0)=9.81(sin⁡35+0.08cos⁡35)=6.3ms2  Finally the speed can be found using:  v=2as+u2=2(−6.3)(2.5)+122=10.6ms  Part B  First calculate the friction force  F=μmgcos⁡0=0.08(60)(9.8)cos⁡35=38.5N  Next multiply the friction by the distance to get the work  W=sF=2.5(38.5)=96.3j

A 60kg skier with an initial speed of 12 m/s coasts up a 2.5 m high rise that ma

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