Does any solid Ag2CrO4 form when 2.7×10−5 g of AgNO3 is dissolved in 15.0 ml...

CheemnCatelvew

Answered question

2021-05-12

Does any solid $A{g}_{2}Cr{O}_{4}$ form when $2.7\times {10}^{-5}$ g of $AgN{O}_{3}$ is dissolved in 15.0 ml of $4.0\times {10}^{-4}\text{}{K}_{2}Cr{O}_{4}$?

Answer & Explanation

Talisha

Skilled2021-05-14Added 93 answers

Balanced reaction-:
$2AgN{O}_{3}\left(aq\right)+{K}_{2}Cr{O}_{4}\left(aq\right)\to A{g}_{2}Cr{O}_{4}\left(s\right)+2KN{O}_{3}\left(aq\right)$
Moles of $AgN{O}_{3}=\frac{\text{mass(g)}}{\text{molar mass (g/mol)}}=\frac{2.7\times {10}^{-5}g}{169.86\text{}\frac{g}{m}ol}$ $=1.589\cdot {10}^{-7}$ mol
Molarity of $A{g}^{+}=\frac{\text{moles of solute}}{V\left(L\right)}=\frac{1.589\cdot {10}^{-7}\text{}mol}{0.015\text{}L}=1.059\cdot {10}^{-5}M$
Ksp of $A{g}_{2}Cr{O}_{4}$ $={\left[A{g}^{+}\right]}^{2}\left[Cr{O}_{4}^{2-}\right]$ $1.2\cdot {10}^{-12}={\left[2s\right]}^{2}\left[s\right]$ $4{s}^{3}=1.2\cdot {10}^{-12}$ $s=6.69\cdot {10}^{-5}$ M
Molarity of $A{g}^{+}$ is less than the molar solubility thus ppt will not occur