A copper calorimeter can with mass 0.100 kg contains 0.160 kgof water and 0.018 kg of ice in thermal equilibrium at atmospheric pressure. If 0.750 kg of lead at a temperature is dropped into the calorimeter can, what is thefinal temperature? Assume that no heat is lost to the surroundings.

pancha3

pancha3

Answered question

2021-03-15

A copper calorimeter can with mass 0.100 kg contains 0.160 kgof water and 0.018 kg of ice in thermal equilibrium at atmospheric pressure.
If 0.750 kg of lead at a temperature is dropped into the calorimeter can, what is thefinal temperature? Assume that no heat is lost to the surroundings.

Answer & Explanation

Roosevelt Houghton

Roosevelt Houghton

Skilled2021-03-17Added 106 answers

Mass of ice (mi)=0.018 kg
Latent Heat of ice ( Li ) = 333000 J / kg
Total heat for the melting of ice Qi=miLi
= 5994.0 J
Mass of Lead (mL) = 0.75 kg
Temp. of Lead (tL) = 255 C
Spec.heat capacity of Lead (cL)= 128 J / kg - K
Total heat comes from Lead QL=(mL)(cL)255
=24480 J
Since QL>Qi
So all ice will melt and the temperature will increase up to t C
Mass of water (mw) = 0.16 kg
Temp. difference of water(t)=t C
spec.heat capacity ofwater (Cw) = 4190 J / kg- K
Mass of copper (mcu)=0.100kg
Temp. difference of copper (t)=t C
spec.heat capacity of copper (Ccu) = 386 J / kg-K
Apply:
Principle of calometry
miLi+(micw+mwcw+mcuccu)(t)=mLcL(225t)
=5994.0J+(75.42+670.4+38.6)(t)=96(225t)
=5994.0J+784.42t=2160096t
216005994=(784.42+96)t
t=17.7 C

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?