A copper pot with mass 0.500 kg contains 0.170 kg of water ata temperature of 20.0∘ C. A 0.250-kg block of iron at 85.0∘ C is dropped into the pot. Find the final temperature, assuming no heat loss to the surroundings.

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Asma Vang · Accepted Answer

Let the final temperature be&#039; t &#039; Temp. difference of water (Dt)=(t−20)C∘ spec.heat capacity of water (cw)=4190 Jkg−K Mass of water (mw)=0.170 kg Mass of Copper (mc)=0.5 kg Temp. difference of Copper (Dt)=(t−20)C∘ spec.heat capacity of Copper (cc)=387 Jkg−K Mass of block (mi)=0.25 kg Initial temp. of block (Tli=85∘ C) spec.heat capacity of block (Ci)=448 Jkg−K Temp. difference of ice (Dt)i=(85−t)C∘ Apply; Principle of claorimetry (Cc⋅mc+Cw⋅mw)⋅(Dt)=Ci⋅mi⋅(Dt)i Dt(Dt)i=Ci⋅miCc⋅mc+Cw⋅mw =0.1236 t=27.154∘ C

A copper pot with mass 0.500 kg contains 0.170 kg of water ata temperature of 20.0^\circ C. A 0.250-kg block of iron at 85.0^\circ C is dropped into the pot. Find the final temperature, assuming no heat loss to the surroundings.

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