A battery with EMF 90.0 V has internal resistance R_b=8.72 Ohms. What is the reading of Vv of a voltometer having totalresstance R_v=500 Ohms when it

vazelinahS

vazelinahS

Answered question

2021-01-22

A battery with EMF 90.0 V has internal resistance Rb=8.72 Ohms. 
What is the reading of Vv of a voltometer having totalresstance Rv=500 Ohms when it is placed across the terminals ofthe battery? 
What is the maximum value that the ratio RbRv may have if thepercent error in the reading of the EMF of a battery is not toexceed 5.00%?

Answer & Explanation

Corben Pittman

Corben Pittman

Skilled2021-01-23Added 83 answers

Step 1

Wher the voltometer is corrected across the terminals of the battery, the total resistence Req=Rb+Rv

=(8.95+440)Ω

=448.95Ω

 Reading of be valtmeter =E448.95×440volt

VV=90448.95×440volt

VV=88.2volt

Step 2

percent error =5%

VV=ERb+Rv×Rv

|VVE|E×100%=5%

|VVE|E=0.05

|E(RVRb+RV)E|E=0.05

|RVRbRV|Rb+RV=0.05

RbRb+RV=0.05

Rb=0.05Rb+0.05RV

0.95Rb=0.05RV

RbRV=0.050.95=119=0.053

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