A concave mirror forms an image on a screen twice as large as theobject. Both the object and screen are then moved to producean image on the screen that is three times the size of theobject. If the screen is moved 75 cm in the process, how faris the object moved? What is the focal length of themirror?

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joshyoung05M · Accepted Answer

1.We know that magnification m = image distance/object distance= image size /object size =v/u =2v = image distanceu =object distancev=2unew magnification = 3 =new image distance/newobjectdistance = v+75/u-x -----1x = extra distance moved by the objectplug v=2u in 1we get u after that substitute in 1/f = 1/-v +1/uplug the values of v and u we get focal length2.If I were to plug V=2u into equation 1, I would end upwith:3 = 2u+75/(u-x)which doesn&#039;t help me solve for either u or x. I thinkthere is a step missing in there.

Accepted Answer

Might be 675, or 450, All we need to is find focal length in each cas and comapre both, and then multiply with each  relation you made

A concave mirror forms an image on a screen twice as large as theobject. Both the object and screen are then moved to producean image on the screen th

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