Particles in a Gold Ring. You have a pure(24-karat) gold ring with mass 17.7 g.Gold has an atomic mass of 197 g/mol</nob> and anatomic number of 79. How many protons? What is pos. charge? With no net charge, How many electrons are in it?
beljuA
Answered question
2020-11-22
Particles in a Gold Ring. You possess a 17.7 g pure (24-karat) gold ring. Gold has an atomic mass of 197 g/mol and anatomic number of 79.
How many protons?
What is pos. charge?
With no net charge, How many electrons are in it?
Answer & Explanation
Roosevelt Houghton
Skilled2020-11-23Added 106 answers
No of moles =
where Av = Avagadro's Number = 6.022*1023 atoms/gm.mol.
m= mass of the gold atom.
A = Atomic weight of atom = 197 gm/mol.
From the above equation we get mass of each goldatom(m).
Total mass = Total number of atoms(n) * Mass of eachatom(m)
Given that Total mass of gold is 17.7gm.
Total number of atoms(n) = 17.7 / Mass of each atom(m)
(a)Number of protons(N) present in the given mass of gold = n *atomic number
(b)Total positive charge = Total number of protons
C.(c) number of electrons is equal to Number ofprotons(N).
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