A 1400 kg block of granite is pulled up an incline at aconstant speed of 1.77 m/s by acable and winch. The coefficient of kinetic frictionbetween the block and the incline is 0.40. What is the power due tothe force applied to the block by the cable?

Lennie Carroll

Lennie Carroll

Answered question

2020-11-07

A 1400 kg block of granite is pulled up an incline at aconstant speed of 1.77 m/s by acable and winch. The coefficient of kinetic frictionbetween the block and the incline is 0.40. What is the power due tothe force applied to the block by the cable?

Answer & Explanation

Clelioo

Clelioo

Skilled2020-11-08Added 88 answers

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Power = Fv (F = force, v = velocity)
Forceon cable = Force of gravity + Force offriction
Fcab=mgsinθ+mgcosθ=mg(sinθ+cosθ)
Use the pythagorean theorem to find the length of the incline:
c=302+402=50
sinθ=oppositehypoteνse=3050=.6
cosθ=adjacenthypoteνse=4050=.8
Substituting Ft in for power yields:
P=mg(sinθ+cosθ)v
Just plug-in the values and solve.

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