A 10.0 m long wire of mass 123 g is stretched under a tensionof 255 N. A pulse is generated at one end, and 20.0 ms later asecond pulse is generated at the opposite end. Where will thetwo pulses first meet?
sibuzwaW
Answered question
2021-02-02
Answer & Explanation
tabuordy
Skilled2021-02-03Added 90 answers
After 20 milli second=0.02 s, the first pulse would have runalong the wire for
This means that it only left 10m-2.88m=7.12m for the 2 pulsesto run.
Thus, the distance which the 2 pulses will first meetwould be
(exactly the same as the answer at the back)
P.S.the remaining distance is divided by 2 as the 2 pulseare moving with the same speed towards each other.
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