Check the solution to "In 1936, Col. Harry Froboess of Switzerland jumped..."

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Efan Halliday

Answered question

2020-12-31

In 1936, Col. Harry Froboess of Switzerland jumped into theocean from the airship Graf Hindenburg, which was 1.20 times 10 tothe 2nd power above the waters

Answer & Explanation

Theodore Schwartz

Skilled2021-01-01Added 99 answers

When he begins to jump he is having only PotentialEnergy.
P.E at this height $= m g h$
= $72.0 \times 9.8 \times 1.20 \times 10^{2}$
= $846.7 \times 10^{2} J$
When he reaches to a height 30 m above the water surface he ishaving potential as well as kinetic energy.
By the conservation of mechanical energy,
$P . E i n i t i a l + K . E i n i t i a l = P . E f i n a l + K . E f i n a l$
$846.7 \times 10^{2} + 0 = m g h^{2} + 0.5 m v^{2}$
$846.7 \times 10^{2} = 72.0 \times 9.8 \times 30.0 + 0.5 \times 72.0 \times v^{2}$
By calculation we can find for v as $42 m / s$

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