A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 and 1510 N , respectively. The acceleration of the cable is 0.620 m/s^2, upward. What is the tension in thecable (a) below the worker and (b) above the worker?

postillan4

postillan4

Answered question

2021-01-10

A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 and 1510 N , respectively. The acceleration of the cable is 0.620 ms2, upward. What is the tension in thecable (a) below the worker and (b) above the worker?

Answer & Explanation

estenutC

estenutC

Skilled2021-01-11Added 81 answers

One way to look at this is to consider that the cable above is supporting both the worker and the crate, while the cable below isjust supporting the crate. In both cases, the tension in the cable must balance the force of gravity, mg, and provide the force to accelerate them upward, ma
So: tension = mg + ma
For the upper cable, use the mass of worker and crate, for the lower cable use just the mass of the crate.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?