Step by step solution to "1. BrO4 What is formal charge and oxidation..."

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glamrockqueen7

Answered question

2021-01-10

1. BrO4
What is formal charge and oxidation number of Oxygen and Bromine?

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irwchh

Skilled2021-01-11Added 102 answers

FC = # valence electrons - ( $\frac{1}{2} \times$ $# bonding electrons + # lone pair electrons)$
Use this formal charge equation and draw the lewis structure
$B r O 4^{- 1}$
Br=7 valence electrons
$O = 6 \times 4 = 24$ valence electrons
Charge of -1 electron means a gain of 1 electron.
Total $= 32$ valence electrons
This lewis structure is a resonance structure with brackets
Outside the bracket is -1 indicating a gain of 1 electron
Br is the central atom with 4 single bonds connecting the 4 oxygen each having a full octet of electrons
$s p^{3}$ hybridization
tetrahedral electron pair geometry and molecular geometry
oxidation number Oxygen is -2
bromine is +7
$x + 4 (- 2) = - 1$
$x - 8 = - 1$
$x = + 7$

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