A soft drink can is h centimeters tall and has a radius of r cm. The cost of material in the can is 0.0015 cents per cm^2 and the soda itself costs 0.002 cents per cm^3. The cans are currently 10 cm tall and have a radius of 2 cm. Use calculus to estimate the effect on costs of increasing the radius by 0.5 cm and decreasing the height by 0.7 cm.

Alexia Avila

Alexia Avila

Answered question

2022-11-03

A soft drink can is h centimeters tall and has a radius of r cm. The cost of material in the can is 0.0015 cents per cm^2 and the soda itself costs 0.002 cents per cm^3. The cans are currently 10 cm tall and have a radius of 2 cm. Use calculus to estimate the effect on costs of increasing the radius by 0.5 cm and decreasing the height by 0.7 cm.

Answer & Explanation

Samuel Hooper

Samuel Hooper

Beginner2022-11-04Added 15 answers

Recall the volume of our cylindrical can is given by V = π r 2 h while its surface area via A = 2 π r h + 2 π r 2 .
The cost of our soda can can be expressed using something along the lines of:
C = ( cost of soda per unit volume ) V + ( cost of can material per unit area ) A .
Here, if we take C to denote the cost of a soda can in cents, we find:
C ( r , h ) = 0.002 π r 2 h + 0.0015 ( 2 π r h + 2 π r 2 )
We can then determine the linearization of the change in C for a given r , h using the total differential:
d C = C r d r + C h d h δ C C r δ r + C h δ h
We're told r = 2 , h = 10 and we want to estimate the change in cost following a change in radius of δ r = 0.5 and change in height of h = 0.7.

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