Suppose that x,y,z∈R with a>0 a constant. Then, is the following true?f(x,y+cz,z)−f(x,y,z)=c∫01(∂x+z∂y)f(x,y+θz,z)dθ.It looks like the...

kuntungw3

kuntungw3

Answered

2022-01-24

Suppose that x,y,zR with a>0 a constant. Then, is the following true?
f(x,y+cz,z)f(x,y,z)=c01(x+zy)f(x,y+θz,z)dθ.
It looks like the mean value theorem for multivariable function but I don't know why x appears.

Answer & Explanation

marzembreax

marzembreax

Expert

2022-01-25Added 13 answers

That looks quite wrong. The right-hand side should be something like cz01yf(x,y+θcz,z)dθ
SaphypycleDapc5

SaphypycleDapc5

Expert

2022-01-26Added 11 answers

f is continuous.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?